The point slope form of an equation of the line that passes through (-4, -3) and (12, 1) is y -1 =1/4(x-12). What is the standard form of the equation for this line?
[tex]y-1=\dfrac{1}{4}(x-12)\qquad|\text{multiply both sides by 4}\\\\4y-4=x-12\qquad|\text{add 12 to both sides}\\\\4y+8=x\qquad|\text{subtract 4y from both sides}\\\\8=x-4y[/tex]
