We are given total 10 tree seedlings.
Number of workshops = 2.
Here order doesn't matters.
When order doesn't matters we apply combination.
We know formula of combination:
[tex]C(n,r) = \frac{n!}{r!(n-r)!}[/tex]
For the given situation, we have
n=10 and r=2.
Plugging values in formula, we get
[tex]\frac{10!}{2!(10-8)!} = \frac{10\times 9\times8!}{2!8!}[/tex]
[tex]\frac{10 \times 9}{2} = \frac{90}{2} =45[/tex]
