Respuesta :

The domain is the same as the x value and the range is the same as the y value, so you just plug in the 3 to all the x's.

[tex]f(x) = 2 ({3})^{2} - 3(3) + 8 \\ f(x) = 18 - 9 + 8 \\ f(x) = 17[/tex]
the range of the function is 17

The value of the range of the function [tex]f(x) = 2x^2-3x+8[/tex] for the domain value 3 is 17

The given function is:

[tex]f(x) = 2x^2-3x+8[/tex]

The domain is a set of all the input values. That is, the domain is a set of all the values of x

The range is a set of the output values. That is, the range is a set of all the values of y

If the domain value is 3, x = 3

Substitute x = 3 into [tex]f(x) = 2x^2-3x+8[/tex]

[tex]f(3) = 2(3)^2-3(3)+8\\f(3) = 2(9) -9+8\\f(3) = 18-9+8\\f(3) = 9+8\\f(3) = 17[/tex]

The range  f(3)  =  17

The value of the range of the function [tex]f(x) = 2x^2-3x+8[/tex] for the domain value 3 is 17

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