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A rubber band has spring constant of 36 N/ m. If you stretch the rubber band 0.02 m past its neutral length, what force does the rubber band apply?

Respuesta :

It's 36 [N/m] x 0.02 [m] = 0.72 N

Answer:

0.72 N

Explanation:

K = 36 N/m, y = 0.02 m

The force applied by teh rubber band is given by

F = - k x y

F = - 36 x 0.02 = - 0.72 N

The negative sign shows the direction of force which is opposite to the direction of displacement.

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