What is the minimum mass of glycerol (c3h8o3) that must be dissolved in 928 mg of water to prevent the solution from freezing at −15.0°c? (assume ideal behavior.)?

Respuesta :

In order to have a freezing point of −15.0°c means we need a depression in freezing point to be −15.0°c

we know that depression in freezing point is a colligative property which depends on molality as

depression in freezing point  = Kf X molality

Kf = 1.86 °C/m

molality = moles of solute / mass of solvent in Kg

15 = 1.86 °C/m X molality

molality = 8.065

molality = moles of glycerol / mass of water in Kg

moles of glycerol = 8.065 X 928 X 10^-6

moles = 0.00748

moles = mass / molar mass

mass = moles X molar mass = 0.00748 X 92 = 0.688 grams = 688 mg

so this is the minimum mass required

The study of chemicals and bonds is called chemistry. The minimum amount at which the liquid state starts converting itself to solid is called the freezing point.

The correct answer is mentioned 688.

What is solidification?

  • The process of conversion of the liquid to the solid is called solidification.

In order to have a freezing point of −15.0°c means we need a depression in freezing point to be −15.0°c. we know that depression in freezing point is a colligative property that depends on molality as

depression in freezing point  =[tex]Kf * molality[/tex]

The data is as follows :-

  • Kf = 1.86 °C/m

[tex]molality = \frac{moles\ of\ solute}{mass \ of\ solvent}15 = 1.86 * molality[/tex]

molality = 8.065

molality =[tex]\frac{moles \ of\ glycerol}{mass \ of\ water}[/tex]

moles of glycerol =[tex]8.065 * 928 * 10^{-6}[/tex]

moles =[tex]0.00748[/tex]

moles =[tex]\frac{mass }{molar mass}[/tex]

mass = [tex]moles * molar mass = 0.00748 * 92\\ = 0.688 grams \\= 688 mg[/tex]

so this is the minimum mass required is 688.

For more information about the molarity, refer to the link:-

https://brainly.com/question/787658