Vertex form for a parabola with vertex (p,q) is
[tex]y = a(x-p)^2 + q[/tex]
We have (p,q)=(-4,5) and another point (-3,2) so we can solve for a:
[tex]2 = a(-3 - -4)^2 + 5[/tex]
[tex]2 = a + 5[/tex]
[tex]a = -3[/tex]
Putting it together,
Answer: [tex]y = -3(x + 4)^2 + 5[/tex]
We could multiply that out if we like but I won't bother.
