Respuesta :
This question is based on law of conservation of momentum, which says total total momentum of the system is equal to total momentum of the system after collision.
Before collision, [tex] m_{1} [/tex] = 340 kg m/s
After collision, [tex] m_{2} [/tex] = mass * velocity = 60 kg * v
Here, we need to find the velocity with which Sheila was thrown after the collision.
According to law of conservation of momentum,
[tex] m_{1} [/tex] = [tex] m_{2} [/tex]
340 = 60 * v
v = 340 / 60 = 5.667 m/s [approximately]
The speed with which Sheila was thrown from the bike is 5.667 m/s.
