Three people are comparing their ages. charlie and ann's ages add to 5 years more than bob's age. charlie and bob's ages add to 6 years more than twice ann's age. ann and bob's ages add to 7 years more than four times charlie's age. set up a system of equations and solve for each person's age.

Question

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Respuesta :

apocritia apocritia · Answer 1 · 2018-08-30T14:35:30+02:00

Solution:

we are given that

Three people are comparing their ages.

Let charlie age be x , ann's ages be y and bob age be z , then we can write using the given info

charlie and ann's ages add to 5 years more than bob's age.

[tex] x+y-z=5 [/tex]

Now using the given info. that charlie and bob's ages add to 6 years more than twice ann's age.

[tex] x+z-2y=6 [/tex]

Again using -ann and bob's ages add to 7 years more than four times charlie's age.

[tex] y+z-4x=7 [/tex]

Now we will solve these three equations together using calculator we get

x=34, y=57 and z=86

Hence charlie age is 34 , ann's ages is 57 and bob age is 86.