Hello!
First of all, we have a 4/52, or 1/13 chance of selecting a pair. Then, we select 1/3 cards 3 times, so we use this as our other fraction.
[tex] \frac{1}{13} [/tex][tex] \cdot \frac{1}{3} [/tex]=[tex] \frac{1}{39} [/tex]
Therefore, we have a 1/39 or about 3%.
I hope this helps!