The given inequality is
[tex] | 9x+ 10 | <15 [/tex]
First we need to remove the absolute sign , and when we do so , we will get a compound inequality, that is
[tex] -15< 9x+10 < 15 [/tex]
To solve for x, first we need to get rid of 10. and for that, we have to do subtraction
[tex] -15-10<9x<15-10
\\
-25 < 9x <5 [/tex]
Now we need to get rid of 9, and for that, we do division
[tex] \frac{-25}{9}< x< \frac{5}{9} [/tex]
So the required solution is
[tex] ( \frac{-25}{9} , \frac{5}{9}) [/tex]
