How many solutions are there to the equation below 9x + 27 = 9( x + 2 ) + 9

Let's solve the equation:
9x+27 = 9(x+2)+9 ← Distribute 9 to the x and 2
9x+27 = 9x+18+9 ← Combine like terms
9x+27 = 9x + 27 ← Subtract 27 from both sides
9x = 9x
Infinitely many solutions would be correct because no matter what x is, it will always equal each other the both sides of the equation because it is 9 times x on both sides.
9x + 27 = 9(x + 2) + 9
Simplify both sides of equation:
9x + 27 = 9(x + 2) + 9
9x + 27 = (9)(x) + (9)(2) + 9 (Distribute)
9x + 27 = 9x + 18 + 9
9x + 27 = (9x) + ( 18 + 9)
(Combine Like Terms:)
9x + 27 = 9x + 27
9x + 27 = 9x + 27
Subtract 9x from both sides:
9x + 27 - 9x = 9x + 27 - 9x
27 = 27
Subtract 27 from both sides:
27 - 27 = 27 - 27
0 = 0
Equations is always true
Answer: All real numbers are solutions: (Infinitely many solutions:)
Hope that helps!!! ( Answer: Letter Choice (B), Infinitely many solutions.).