The distance would be 2√3 , in other words it is 2 square root 3
For this case we use the distance formula between two points.
We have then:
[tex] d=\sqrt{(x2-x1)^2+(y2-y1)^2} [/tex]
Substituting values in the given equation we have:
[tex] d=\sqrt{(6-4)^2+(5\sqrt{2}-3\sqrt{2})^2} [/tex]
Rewriting the equation we have:
[tex] d=\sqrt{(2)^2+(2\sqrt{2})^2} [/tex]
[tex] d=\sqrt{4+8} [/tex]
[tex] d=\sqrt{12} [/tex]
[tex] d=\sqrt{3*4} [/tex]
[tex] d=2\sqrt{3} [/tex]
Answer:
The distance between the points is:
[tex] d=2\sqrt{3} [/tex]
