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Captain gabriela has a ship, the h.m.s. khan. the ship is two furlongs from the dread pirate amos and his merciless band of thieves. the captain has probability \dfrac{3}{4} 4 3 ​ start fraction, 3, divided by, 4, end fraction of hitting the pirate ship. the pirate only has one good eye, so he hits the captain's ship with probability \dfrac{1}{4} 4 1 ​ start fraction, 1, divided by, 4, end fraction. if both fire their cannons at the same time, what is the probability that the pirate hits the captain's ship, but the captain misses?

Respuesta :

sqdancefan
P(pirate hits) = 1/4
P(captain misses) = 1 - 3/4 = 1/4

We assume these events are independent, so their joint probability is the product of their individual probabilities:
  P(pirate hits & captain misses) = (1/4)·(1/4) = 1/16

Answer:

answer is 1/10

Step-by-step explanation:

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