Be sure to use proper significant figures. The molecular weight of NaCl is 58.44 grams/mole. To prepare a 0.50 M solution: You would need to have grams of NaCl in 1,000 mL of water.\

Your answer would be,
Molarity = moles of solute/volume of solution we needed, 29.22(g)(mol) of NaCI

= 29.22(g)/58.44(g)(mol^-1)(1)/1(L)
= 0.500(mol)(L^-1)

Hope that helps!!!

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kumaripoojavt kumaripoojavt · Answer 2 · 2022-07-16T09:00:47+02:00

29.22g is grams of NaCl in 1,000 mL of water.

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

Molarity of solution = 0.50 M

Volume of solution = 1,000 mL =1 L

Molar mass of NaCl (solute) = 58.44 g/mole

Formula used :

[tex]Molarity =\frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]

[tex]0.50 M =\frac{Mass of NaCl }{Molar \;mass \;of \;NaCl X 1L }[/tex]

[tex]0.50 M =\frac{Mass \;of \;NaCl }{58.44 X 1L }[/tex]

29.22g

Hence, 29.22g is grams of NaCl.

Learn more about moles here:

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