1. If you have jogged 5 miles from the park at a rate of r miles per hour, then the time you need to do this is [tex] \frac{5}{r} [/tex] hours ([tex]S=v\cdot t[/tex], where S is distance, v-speed and t-time).
2. When you run back to the park, your average speed increases by 1 mph and become r+1 mph.
3. It takes [tex] \frac{5}{r+1} [/tex] hours to jog 5 miles back to the park
4. The total jogging time T is [tex] \frac{5}{r} + \frac{5}{r+1} [/tex] hours.
5. If you jogged away from the park at an average speed of 4 miles per hour, then r+1=4 and r=3. The expression [tex] \frac{5}{r} + \frac{5}{r+1} [/tex]will take look
[tex] \frac{5}{3} + \frac{5}{4}=\frac{5\cdot4+5\cdot 3}{12} =\frac{35}{12}=2.9 [/tex]hours.