Answer:
Option D is correct.
Step-by-step explanation:
We will find the volume of figure 1:
V1 = [tex]18\times21\times36+\frac{1}{3}\times36\times21\times9[/tex]
= [tex]13608+2268=15876[/tex] cubic feet
We will now find the volume of figure 2:
V2 = [tex]36\times21\times18+\frac{1}{2}\times36\times21\times9[/tex]
= [tex]13608+3402=17010[/tex] cubic feet
Now, the difference of volumes of both figures = [tex]17010-15876=1134[/tex] cubic feet.
Hence, the volume of figure 2 is more than figure 1 by 1134 cubic feet.