Respuesta :

Dejanras
Answer is: 2.43 mol of water.
Balanced chemical reaction: 2Na + 2H₂O → 2NaOH + H₂.
m(Na) = 56 g.
n(Na) = m(Na) ÷ M(Na).
n(Na) = 56 g ÷ 23 g/mol.
n(Na) = 2.43 mol.
From chemical reaction: n(Na) : n(H₂O) = 2 : 2 (1 : 1).
n(H₂O) = 2.43 mol.
m(H₂O) = 2.43 mol · 18 g/mol.
m(H₂O) = 43.82 g.
sebassandin

Answer:

n_{H_2O}=2.43molH_2O

Explanation:

Hello,

The carried out reaction is:

[tex]2Na+2H_2O-->2NaOH+H_2[/tex]

Thus, the moles of water that react with 56.0 g of sodium are computed as follows:

[tex]n_{H_2O}=56.0gNa*\frac{1molNa}{23gNa}*\frac{2molH_2O}{2molNa}\\n_{H_2O}=2.43molH_2O[/tex]

Best regards.