Respuesta :
First find the derivative of f(x):-
f'(x) = 3x^2 - 12x + 8
So instantaneous rate at x = 3
= 3(3)^2 - 12(3) + 8
= 27 - 36 + 8 = -1 answer
f'(x) = 3x^2 - 12x + 8
So instantaneous rate at x = 3
= 3(3)^2 - 12(3) + 8
= 27 - 36 + 8 = -1 answer
The instantaneous rate of change is how much a function changes, at that a particular point
The instantaneous rate of change of f(x) at x =3 is [tex]-\frac{5}{3}[/tex]
The function is given as:
[tex]f(x) =x^3 - 6x^2 + 8x - 2[/tex]
And the point is given as:
[tex]x = 3[/tex]
The instantaneous rate of change (r) is calculated as:
[tex]r = \frac{f(x)}{x}[/tex]
So, we have:
[tex]r=\frac{x^3 - 6x^2 + 8x - 2}{x}[/tex]
Substitute 3 for x
[tex]r=\frac{3^3 - 6 \times 3^2 + 8\times 3 - 2}{3}[/tex]
[tex]r=\frac{-5}{3}[/tex]
Rewrite as:
[tex]r= -\frac{5}{3}[/tex]
Hence, the instantaneous rate of change of f(x) at x =3 is [tex]-\frac{5}{3}[/tex]
Read more about instantaneous rate of change at:
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