We need to convert the equation of the circle to standard form only then we can find the radius and the center of the circle.
[tex]x^{2} +2x+ y^{2}-2y-14=0 \\ \\
x^{2} +2x+ y^{2}-2y=14 \\ \\
x^{2} +2(x)(1)+ y^{2}-2(y)(1)=14 \\ \\
x^{2} +2x+1 + (y^{2}-2y+1)=14+1+1 \\ \\
(x+1)^{2}+(y-1)^{2} =16
[/tex]
From this equation we can write:
Center of the circle is (-1,1) and the radius of the circle is 4.
