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hi i'm having trouble solving this question

" if 7.54 grams of Al reacts with excess of H2SO4, and makes 0.33g of H2 . What is the % yield of H2gas produced? 

hi im having trouble solving this question if 754 grams of Al reacts with excess of H2SO4 and makes 033g of H2 What is the yield of H2gas produced class=

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Dejanras
Answer is:  the % yield of hydrogen gas produced is 58.9%.
m(Al) = 7.54 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 7.54 g ÷ 27 g7mol.
n(Al) = 0.28 mol; amount of substance.
From chemical reaction: n(Al) : n(H₂) = 1 : 1.
n(H₂) = 0.28 mol.
m(H₂) = 0.28 mol · 2 g/mol.
m(H₂) = 0.56 g.
%yield = 0.33 g ÷ 0.56 g · 100%.
%yield = 58.9%.

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