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Please help me!

The students in Mr. McIntyre’s class and the students in Mrs. Ramos’s class were asked how many pets they each have. The dot plots below show the results. Which compares the means of the data in the dot plots?

The mean for Mr. McIntyre’s class is about 2 more than the mean for Mrs. Ramos’s class.

The mean for Mrs. Ramos’s class is about 2 more than the mean for Mr. McIntyre’s class.

The mean for Mr. McIntyre’s class is about 1 more than the mean for Mrs. Ramos’s class.

The mean for Mrs. Ramos’s class is about 1 more than the mean for Mr. McIntyre’s class.

*The first picture is Mr. McIntyre’s Class
*The second picture is Mrs. Ramos’s Class

Will give branliest Please help me The students in Mr McIntyres class and the students in Mrs Ramoss class were asked how many pets they each have The dot plots class=
Will give branliest Please help me The students in Mr McIntyres class and the students in Mrs Ramoss class were asked how many pets they each have The dot plots class=

Respuesta :

mayadc821
The mean can be calculated by adding all of the values and dividing that sum by the number of values you added.  To take advantage of the way data is being collected, I am grouping the addends as, for example, 5(1), instead of writing out 1 + 1 + 1 + 1 + 1.

Mr. McIntyre's class mean is:
[tex]\frac{5(0)+5(1)+4(2)+ 1(3)}{5 + 5+4+1} = \frac{5+8+ 3}{15}= \frac{16}{15}= approx. 1.07[/tex]

Mrs. Ramos' class mean is:
[tex] \frac{1(0)+2(1)+2(2)+4(3)+3(4)+3(5)}{1+2+2+4+3+3} = \frac{2+4+12+12+15}{15}= \frac{45}{15}=3[/tex]

Based on these findings, we can conclude that the mean for Mrs. Ramos' class is about 2 more than the mean for Mr. McIntyre's class.
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Answer:

If you are lazy like me the answer is B

Step-by-step explanation:

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