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Assume that 8.5 L of iodine gas are produced at STP according to the following balanced equation:
2Kl+Cl2->2KCl+I2
How many moles of I2 are produced? How many moles of Cl2 are used?
How many grams of Cl2 are used?

Respuesta :

transitionstate
Balanced chemical equation is as;

                                  2 Kl  +  Cl₂     →     2 KCl  +  I₂

1)  Moles of I₂ produced;

             22.4 L volume is occupied by   =  1 mole of I₂ at STP
So,
             8.5 L of I₂ will be occupied by  =  X mole of I₂ at STP

Solving for X,
                       X  =  (8.5 L × 1 mol) ÷ 22.4 L

                       X  =  0.379 Moles of I₂ 

2)  Moles of Cl₂ used;

                         22.4 L I₂ utilized  =  1 mole of Cl₂  gas
So,
                    8.5 L of I₂ will utilize =  X mole of Cl₂  gas

Solving for X,
                       X  =  (8.5 L × 1 mol) ÷ 22.4 L

                       X  =  0.379 Moles of Cl₂ 

3)  Grams of Cl₂ used;

As,
                       Moles  =  Mass / M.mass
Or,
                       Mass  =  Moles × M.mass

                       Mass  =  0.379 mol × 70.90 g.mol⁻¹

                       Mass  =  26.87 grams of Cl₂

The study of chemicals and bonds is called chemistry. There are two types of solution and these are the acidic and basic solutions.

The correct answer to the question is 26.87

What are moles?

  • The mole is the base unit of the amount of substance in the International System of Units.
  • It is defined as exactly 6.02214076×10²³ elementary entities, which may be atoms, molecules, ions, or electrons

A balanced chemical equation is as follows:-

[tex]2 Kl + Cl_2 ------> 2 KCl + I_2[/tex]

The Moles of I₂ produced;

  • 22.4 L volume is occupied by   =  1 mole of I₂ at STP
  • 8.5 L of I₂ will be occupied by  =  X mole of I₂ at STP

The value of  X is:-

  • X  =  [tex]\frac{(8.5 L * 1 mol)}{22.4} L[/tex]
  • X  =  [tex]0.379[/tex] Moles of I₂

The Moles of Cl₂ used is as follow:-

  • 22.4 L I₂ utilized  =  1 mole of Cl₂  gas
  • 8.5 L of I₂ will utilize =  X mole of Cl₂  gas

The value of X is;-

  • X  =  [tex]\frac{(8.5 L * 1 mol)}{22.4 L}[/tex]
  • X  = [tex]0.379[/tex]Moles of Cl₂

The Grams of Cl₂ used as follow

[tex]Moles = \frac{Mass}{M.mass}[/tex]

[tex]Mass = Moles * M.mass\\Mass = 0.379 mol * 70.90\\Mass = 26.87 \ grams \ of CL_2[/tex]

Hence, the correct answer is 26.87 grams.

For more information about the mole, refer to the link:-

https://brainly.com/question/15209553

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