PLEASE HELP!!! DUE TODAY, GIVING 100 POINTS
Data
Trial 1
Trial 2
Mass of empty crucible with lid
26.695g
26.695
Length of ribbon cut
1in
4in
Mass of Mg metal, crucible, and lid
26.949g
27.097
Mass of MgO, crucible, and lid
27.109g
27.358
Calculations
Show your calculations for each of the following. Remember, calculations should follow rules for significant figures.
Remember to use the balanced chemical reaction: 2Mg(s) + O2(g) → 2MgO(s).
Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of Mg, crucible, and lid (row 2 in the chart) to find the mass of magnesium for each trial.
Trial 1: 0.254

Trial 2: 0.402

Subtract the mass of the crucible and lid (row 1 in the chart) from the total mass of MgO, crucible, and lid (row 3 in the chart) to find the mass of magnesium oxide for each trial. This is the actual yield of magnesium oxide for each trial.
Trial 1: 0.414

Trial 2: 0.663

Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial using stoichiometry.
Trial 1:

Trial 2:

Determine the percent yield of MgO for your experiment for each trial.
Trial 1:

Trial 2:
Determine the average percent yield of MgO for the two trials.